A dock worker applies a constant horizontal force of 79.0 N to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves 11.0 m in the first 6.00 s.
What is the mass of the block of ice?
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Use the fact that the work done equals the change in kinetic energy.
F X = (1/2) M V^2
X is the distance moved. F is the force. The final velocity (after 6 seconds)is V. Since it accelerates uniformly, the average velocity 11/6 m/s is half the final velocity.
V = 22/6 = 3.667 m/s
Now solve the first equation for M.
M = 2 F X/ V^2
1 answer
189.5
2 answers