d = (1/2) a t^2
10 = (1/2)a (36)
a = 20/36
then
F = m a
80 = m (20/36)
so
m = 36 * 80 / 20
A dock worker applies a constant horizontal force of 80.0N to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves 10.0m in the first 6.00s. What is the mass of the block of ice?
1 answer