A dock worker applies a constant horizontal force of 80.0N to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves 10.0m in the first 6.00s. What is the mass of the block of ice?

Answer 1

d = (1/2) a t^2

10 = (1/2)a (36)

a = 20/36

then
F = m a
80 = m (20/36)
so
m = 36 * 80 / 20