(P1V1/T1)= (P2V2/T2)
T must be in kelvin.
a diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15 degrees celcius. What is the volume of the bubble when it reaches the surface where the pressure is 1.0 atm and the temperature is 27 degrees celcius
4 answers
580 mL
(P1*V1/T1) = (P2*V2/T2)
(T2*P1*V1/P2*T1) = V2
15+273=288 27+273=300
(300*2.4*250/1*288) = 625mL round to 630mL
answer 630mL
(T2*P1*V1/P2*T1) = V2
15+273=288 27+273=300
(300*2.4*250/1*288) = 625mL round to 630mL
answer 630mL
625 mL= round to 630 mL