Use PV = nRT and solve for n = number of moles.
Then remember 1 mole of a gas contains 6.022E23 molecules.
a diver exhales a bubble with a volume of 250mL at a pressure of 2.4atm and a temp. of 15*C. How many gas particles are in this bubble?
4 answers
so is it 2.9 E26??
If you had shown your work I could find your error.
PV = nRT or n = PV/RT
n = (2.4atm x 0.25L)/(0.08206L*atm x 288 K) = 0.0254 moles.
0.0254 moles x 6.022E23 = approximately 1.5E22 molecules.
PV = nRT or n = PV/RT
n = (2.4atm x 0.25L)/(0.08206L*atm x 288 K) = 0.0254 moles.
0.0254 moles x 6.022E23 = approximately 1.5E22 molecules.
k thanks so much for your help!
5 answers