Let's call the number of cars sold by Dealership A "x".
According to the problem, Dealership B sells twice as many cars as Dealership A, so the number of cars sold by Dealership B is 2x.
Dealership B also sells half as many trucks as Dealership A. If Dealership A sells "x" total cars and trucks, then it sells x - x/2 = x/2 trucks. Similarly, Dealership B sells (2x)/2 = x/2 trucks.
To find the total number of cars and trucks sold by Dealership A and Dealership B, we can add the number of cars and trucks sold separately.
Dealership A sells x cars and x/2 trucks, so the total number of cars and trucks sold by Dealership A is x + x/2 = 3x/2.
Dealership B sells 2x cars and x/2 trucks, so the total number of cars and trucks sold by Dealership B is 2x + x/2 = 5x/2.
According to the problem, the total number of cars and trucks sold by both dealerships is 229.
Therefore, we can set up the following equation:
3x/2 + 5x/2 = 229
Adding the fractions on the left side of the equation, we get:
8x/2 = 229
Simplifying the left side of the equation, we get:
4x = 229
Dividing both sides of the equation by 4, we get:
x = 57.25
Since we can't have a fractional number of cars sold, Dealership A sold 57 cars.
a company owns two dealerships both of which sell cars and trucks. Dealership A sells a total of 164 cars and trucks dearlership B sells twice as many cars and half as many trucks as Dealership A. and sells a total of 229 cars and trucks
How many cars did dealership A sell
1 answer
1 answer