a) The equation for the total cars and trucks for Dealership A is:
C + T = 164
where C represents the number of cars and T represents the number of trucks.
b) The equation for the total cars and trucks for Dealership B is:
2C + (1/2)T = 229
where C represents the number of cars and T represents the number of trucks.
c) We can solve the equation C + T = 164 to find the number of cars Dealership A sold:
C + T = 164
C + T - T = 164 - T
C = 164 - T
d) Considering that Dealership B sold half as many trucks as Dealership A, we can substitute the value of T from equation c into equation b:
2C + (1/2)T = 229
2(164 - T) + (1/2)T = 229
328 - 2T + (1/2)T = 229
(1/2)T = 229 - 328 + 2T
(1/2)T = -99 + 2T
(1/2)T - 2T = -99
-3/2 T = -99
T = (-99)/(-3/2)
T = 66
Therefore, Dealership A sold 66 trucks.
A company owns two dealerships, both of which sell cars and ttrucks. Dealership A sells a toal of 164 cars and trucks. Dealership B sells twice as many cars and half as many trucks as Dealership A, and sells a total of 229 cars and trucks.
a) An equation for the total cars and trucks for Dealership A:
b) An equation for the total cars and trucks for dealership B:
c) How many cars did Dealership A sell?
d)Considering that Dealership B sold half as many trucks as Dealership A, how many trucks did Dealership B sell?
1 answer
1 answer