a) Let x be the number of cars and y be the number of trucks sold by Dealership A. Since Dealership A sold a total of 225 cars and trucks, the equation can be written as:
x + y = 225
b) Let a be the number of cars and b be the number of trucks sold by Dealership B. Since Dealership B sold twice as many cars and half as many trucks as Dealership A, the equation can be written as:
a + b = 300
c) To find the number of cars sold by Dealership A, we can substitute y = 225 - x into the equation a + b = 300:
x + (225 - x) = 300
Simplifying the equation, we get:
225 = 300
Therefore, Dealership A sold 225 cars.
d) Given that Dealership B sold half as many trucks as Dealership A, we can substitute y/2 for b in the equation a + b = 300:
x + (y/2) = 300
Since we know that x = 225, we can substitute it into the equation:
225 + (y/2) = 300
Simplifying the equation, we get:
(y/2) = 75
Multiplying both sides by 2, we get:
y = 150
Therefore, Dealership B sold 150 trucks.
Use your graphing calculator
A company owns two dealerships, both of which sell cars and trucks. Dealership A sells a total of 225 cars and trucks. Dealership B sells twice as many cars and half as many trucks as the Dealership A, and sells a total of 300 cars and trucks.
a) An equation for the total cars and trucks for Dealership A:
b) An equation for the total cars and trucks for Dealership B:
c) How many cars did Dealership A sell?
d) Given the fact that Dealership B sold half as many trucks as Dealership A, how many trucks did Dealership B sell?
1 answer
1 answer