You have to integrate F dx to get Work, and the force function F(x) changes its functional form over the integration interval.
In the first problem, the interval of 2.4*10^4 x dx from 0 to 0.21 m is
1.2*10^4*(0.21)^2. To that, you have to add the integral of 5880 dx from 0.21 to 0.30 m. That is just 5880 * 0.09
Do the second problem the same way.
A block is acted on by a force that varies as (2.8*10^4 N/m)x for 0<=x<=.21m, and then remains constant at 5880 N for larger x.
1. How much work does the force do on the block in moving it from x = 0 to x = 0.30 {m}?
2. How much work does the force do on the block in moving it from x = 0.10 {m} to x = 0.40m?
I've tried most formulas i'm sure i only mess up when i forget something. Please help me pleasee
1 answer
1 answer