Asked by Juan

A 0.60-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 9.0 N for a distance of 2.0 m. How much farther would the force have to act for the block to have 72 J of kinetic energy?
Answered by Scott
work = energy

72 J / 9 N = 8 m
Answered by Juan
It's not correct, that´s what the platform says
Answered by Damon
Did not subtract work already done
9*2 = 18 J
72 - 18 = 54
54/9 = 6 meters
Answered by Juan
@Damon thanks a lot!
Answered by Damon
You are welcome.
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