Asked by ROMAN
A 6.53-kg block initially at rest is pulled to the right along a horizontal surface by a
constant force of 125 N applied at an angle θ above the horizontal. The coefficient of
kinetic friction between the block and the horizontal surface is 0.150. At what angle θ
above the horizontal surface should the force be applied to achieve the largest possible
speed after the block has moved 5.00 m to the right?
constant force of 125 N applied at an angle θ above the horizontal. The coefficient of
kinetic friction between the block and the horizontal surface is 0.150. At what angle θ
above the horizontal surface should the force be applied to achieve the largest possible
speed after the block has moved 5.00 m to the right?
Answers
Answered by
bobpursley
to get the largest speed, you need the largest accelerating force.
The force pulling up reduces weight, thus friction. So there is an optimum angle.
Net force=m*a
125CosTheta-(mg*mu(1-sinTheta))=ma
so you want to maximize a. Take the derivative of each side with respect to theta.
-125SinTheta-(mg*mu)(-cosTheta)=0
TanTheta=mg*mu/125
check all that.
The force pulling up reduces weight, thus friction. So there is an optimum angle.
Net force=m*a
125CosTheta-(mg*mu(1-sinTheta))=ma
so you want to maximize a. Take the derivative of each side with respect to theta.
-125SinTheta-(mg*mu)(-cosTheta)=0
TanTheta=mg*mu/125
check all that.
Answered by
Physics Professor
Pay the 20 dollars or use the book to solve it.
Answered by
Anonymous
Get back to school and ask your Teacher to teach u back!?
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