Asked by Maninder Buttar
a block of mass 5kg initially at rest at the origin is acted on by a force along the position X direction represented by F=(20+5x)N calculate the work done by the force during the displacement of the block from x=0 at x=4m
Answers
Answered by
Damon
integral F dot dx from x = 0 to x = 4
int [ 20 + 5 x ] dx = 20 int dx + 5 int x dx
= 20 (4 - 0) + 5 (.5 * 4^2 - .5 * 0^2)
= 80 + 40
= 120 Joules
int [ 20 + 5 x ] dx = 20 int dx + 5 int x dx
= 20 (4 - 0) + 5 (.5 * 4^2 - .5 * 0^2)
= 80 + 40
= 120 Joules
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