Asked by Anonymous

A ball dropped from a sixth floor window accelerates at 10 m/s
After 2 seconds it hits the
ground. It bounces back with a
velocity of
-15 m/s.
What is the ball’s velocity
when it hits the ground?
What is the change in velocity of the ball when it bounces?
The ball is in contact with the ground for 0.2 s when it bounces. What is
its mean acceleration while it is
in contact with the ground?

Answers

Answered by bobpursley
think. The velocity at impact had to be 15m/s if the bounce was elastic.
change velocity=(vf-Vi)=-15-15=-30m/s

Acceleration= changevelociyt/time
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