Asked by Brendan Zankowski
A ball is dropped from $405$ meters and rebounds two-thirds the distance it falls each time it bounces. How many meters will the ball have traveled when it hits the ground the fourth time?
Answers
Answered by
Reiny
distance covered in bounce #1 -- 405 metres
distance covered in bounce #2 --- 2(2/3)(405) = 540 m, 270 each way
distance covered in bounce #3 = 2(2/3)(270) = 360 m , 180 each way
distance covered in bounce #4 = 2(2/3)(180) = 240 m
add them up
distance covered in bounce #2 --- 2(2/3)(405) = 540 m, 270 each way
distance covered in bounce #3 = 2(2/3)(270) = 360 m , 180 each way
distance covered in bounce #4 = 2(2/3)(180) = 240 m
add them up
Answered by
Brendan Zankowski
Im sorry, but check your work, when I input the answer, 1095, it says wrong
Answered by
Reiny
Don't know how you got that answer, but ...
405 + 540+360+240 = 1545
405 + 540+360+240 = 1545
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