Asked by Amy
A ball dropped from a sixth floor window accelerates at 10m/s squared. After 2 seconds it hits the ground. It bounces back with a velocity of -15m/s squared.
A. What is the balls velocity when it hits the ground?
b. The ball is in contact with the ground for 0.02 s when it bounces. What is its mean acceleration while it is in contact with the ground?
A. What is the balls velocity when it hits the ground?
b. The ball is in contact with the ground for 0.02 s when it bounces. What is its mean acceleration while it is in contact with the ground?
Answers
Answered by
Steve
two problems here:
1. velocity is not in m/s^2
2. It should bounce back with an upward (positive) velocity.
1. velocity is not in m/s^2
2. It should bounce back with an upward (positive) velocity.
Answered by
Amy
sorry
A ball dropped from a sixth floor window accelerates at 10m/s squared. After 2 seconds it hits the ground. It bounces back with a velocity of -15m/s.
A ball dropped from a sixth floor window accelerates at 10m/s squared. After 2 seconds it hits the ground. It bounces back with a velocity of -15m/s.
Answered by
Amy
this is what the worksheet says, that is why im soo confused
Answered by
bobpursley
see the problem
http://www.jiskha.com/display.cgi?id=1380223491
Steve said it should bounce back at 15, but that presumes upward as + direction. One can make it the - direction, but that is seldom done. The direction signs are arbritary.
http://www.jiskha.com/display.cgi?id=1380223491
Steve said it should bounce back at 15, but that presumes upward as + direction. One can make it the - direction, but that is seldom done. The direction signs are arbritary.
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