A 0.40kg ball, attached to the end of a horizontal cord, is rotated in a circle of radius 2.1m on a frictionless horizontal surface.If the cord will break when the tension in it exceeds 80N , what is the maximum speed the ball can have?

Answer 1

M V^2/R = 80 N

R = 2.1 m
M = 0.40 kg

Solve for V

Answer 2

1.2 m/s