max tension= m*v^2/r
solve for v.
A 0.40 kg ball, attached to the end of a horizontal cord, is rotated in a circle of radius 1.5 m on a frictionless horizontal surface. The cord will break when the tension in it exceeds 61 N.
What is the maximum speed the ball can have?
4 answers
15.12
2341234
61=0.40v^2/1.5
91.5=0.40v^2
228.75=v^2
15.12=v
91.5=0.40v^2
228.75=v^2
15.12=v
1 answer