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A 0.40-kg ball, attached to the end of a horizontal cord, is rotated in a circle of radius 2.0 m on a frictionless horizontal surface.

If the cord will break when the tension in it exceeds 75 N, what is the maximum speed the ball can have?

May someone please walk me through this problem step by step

1 answer

ma = T
ma = mv²/R
mv²/R= T
v=sqrt(R•T/m)

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