if 6 oz of dough are needed to make an 8-in. pizza, how much dough will be needed to make a 16-in. pizza of the same thickness? (compare the areas of the pizza tops)
i don't know what to do
5 answers
Set up a ratio oz/in. so you have 6/8 to x/16. Then you cross mutiply so you have 16*6=8x. 16*6=96 ,SO 96=8x. Then you divide 96 by 8 to get 12. so you will need 12 oz. of dough
or you could just notice that the numbers are just double and double 6 to=12
the answers 24. i looked at the answers cus i thought it was 12 too
nope. i figured it out. you have to use pi to find the areas of both pizzas and then their ratio is 1:4 so 6*4 = 24
you do not need pi. It cancels.
r1 = 4 inches
r2 = 8 inches
since thickness is the same:
volume2 = volume1 (pi r2^2 /pi r1^2)
volume2 / volume 1 = (8^2/4^2) = 4
so
volume2 = volume1 * 4
mass2 = 6 * 4 = 24
r1 = 4 inches
r2 = 8 inches
since thickness is the same:
volume2 = volume1 (pi r2^2 /pi r1^2)
volume2 / volume 1 = (8^2/4^2) = 4
so
volume2 = volume1 * 4
mass2 = 6 * 4 = 24