Question
A loaded sled is pulled by means of a rope that makes an angle of 45.0° with the horizontal. If the mass of the sled is 60.0 kg and the coefficient of friction is 0.020, how much work is done in pulling the sled for a distance of 1.000 km?
Answers
Henry
Fap*cos45-u*mg = m*a
Fap*cos45-0.02*588 = m*0 = 0
Fap * cos45 - 11.76 = 0
Fap*cos45 = 11.76 N. = Hor. component of Force applied.
Work = 11.76 * 1000. = 11,760 Joules.
Fap*cos45-0.02*588 = m*0 = 0
Fap * cos45 - 11.76 = 0
Fap*cos45 = 11.76 N. = Hor. component of Force applied.
Work = 11.76 * 1000. = 11,760 Joules.