Asked by Mike

A 39.5 kg sled is pulled forward with a 72.8 N force which causes an acceleration of 0.521 m/s how much friction force acts on the sled
Answered by oobleck
The net force causing the acceleration is
F = ma = 39.5 * 0.521 = 20.58N
So now you can get how much was used to overcome the opposing force of the friction.
Answered by henry2,
F-Ff = M*a.
72.8-Ff = 39.5 * 0.521,
Ff = Force of friction = ?

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