Question
150n sled is pulled by 28° slope with constant speed by 100n force. What is the cofficent of kinatic friction slead and the slope.
Answers
Anonymous
normal force on ground = m g cos 28 = 150 * 0.883 = 132.4 Newtons
so 133.4 * mu = friction force back down slope
component of weight down slope = m g sin 28 = 150*0.469 = 70.4 Newtons
so
133.4 * mu + 70.4 = 100
133.4 mu = 29.6
mu = 0.222
so 133.4 * mu = friction force back down slope
component of weight down slope = m g sin 28 = 150*0.469 = 70.4 Newtons
so
133.4 * mu + 70.4 = 100
133.4 mu = 29.6
mu = 0.222