Asked by Rob
A 16-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 35 N. Starting from rest, the sled attains a speed of 2.1 m/s in 9.5 m. Find the coefficient of kinetic friction between the runners of the sled and the snow.
Answers
Answered by
Jennifer
35 - ckf * 16 = m*a
where ckf is coefficient of kinetic friction. In your textbook ckf is probably represented as the greek letter mu, but it's really hard to write greek letters here. . .
m is the mass of the sled, and a is its acceleration.
x = 1/2 * a * t^2
v = a * t
where x is the distance traveled by the sled, t is time, and v is the speed
so
9.5 = 1/2 * a * t^2
2.1 = a * t
Using algebra:
t = 2.1/a
plugging into the equation for x:
9.5 = (1/2 * 2.1^2)/a
Use algebra to solve for the acceleration, then plug into
35 - ckf * 16 = 16*a
and solve for ckf
where ckf is coefficient of kinetic friction. In your textbook ckf is probably represented as the greek letter mu, but it's really hard to write greek letters here. . .
m is the mass of the sled, and a is its acceleration.
x = 1/2 * a * t^2
v = a * t
where x is the distance traveled by the sled, t is time, and v is the speed
so
9.5 = 1/2 * a * t^2
2.1 = a * t
Using algebra:
t = 2.1/a
plugging into the equation for x:
9.5 = (1/2 * 2.1^2)/a
Use algebra to solve for the acceleration, then plug into
35 - ckf * 16 = 16*a
and solve for ckf
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