Asked by carol
a 2.00 lb rock is dropped from a bridge to the water 50 below.
a. what is the velocity as it hits the water?
b. how long does it take to hit the water?
c. What is its kinetic energy as it hits the H2o?
a. what is the velocity as it hits the water?
b. how long does it take to hit the water?
c. What is its kinetic energy as it hits the H2o?
Answers
Answered by
Henry
Ht. = 50 m.?
a. V^2 = Vo^2 + 2g*h
V^2 = 0 + 19.6*50 = 980
V = 31.3 m/s.
b. V = Vo + g*t = 31.3 m/s.
0 + 9.8t = 31.3
t = 3.19 s.
c. m = 2.0Lb * 0.454kg/Lb = 0.908 kg.
KE = m*V^2/2 = 0.908*31.3^2/2 = 444.8 J.
a. V^2 = Vo^2 + 2g*h
V^2 = 0 + 19.6*50 = 980
V = 31.3 m/s.
b. V = Vo + g*t = 31.3 m/s.
0 + 9.8t = 31.3
t = 3.19 s.
c. m = 2.0Lb * 0.454kg/Lb = 0.908 kg.
KE = m*V^2/2 = 0.908*31.3^2/2 = 444.8 J.
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