A rock is dropped from a 600 foot tower.

The height of the rock as a function of time
can be modeled by the equation:
h(t) = −16t
2
+ 600. During what period of
time will the height of the rock be greater
than 300 above the ground?

1 answer

height = -16t^2 + 600
when does it reach a height of 300?
300 = -16t^2 + 600
16t^2 = 300
t^2 = 300/16
t = √300/4
= 10√3/4 = appr 4.33 seconds

It will be above or equal to a height of 300 ft for the first 4.33 seconds