Asked by Anonymous
A rock is dropped from a 600 foot tower.
The height of the rock as a function of time
can be modeled by the equation:
h(t) = −16t
2
+ 600. During what period of
time will the height of the rock be greater
than 300 above the ground?
The height of the rock as a function of time
can be modeled by the equation:
h(t) = −16t
2
+ 600. During what period of
time will the height of the rock be greater
than 300 above the ground?
Answers
Answered by
Reiny
height = -16t^2 + 600
when does it reach a height of 300?
300 = -16t^2 + 600
16t^2 = 300
t^2 = 300/16
t = √300/4
= 10√3/4 = appr 4.33 seconds
It will be above or equal to a height of 300 ft for the first 4.33 seconds
when does it reach a height of 300?
300 = -16t^2 + 600
16t^2 = 300
t^2 = 300/16
t = √300/4
= 10√3/4 = appr 4.33 seconds
It will be above or equal to a height of 300 ft for the first 4.33 seconds
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