Asked by hannah
a 2.00 kg rock is dropped from a bridge to the water 50.0m below. what is the velocity as it hits the water? what is its kinetic energy as it hits the water?
Answers
Answered by
Elena
PE=KE
mgh=mv^2/2
v=sqrt(2gh)
KE= mv^2/2
mgh=mv^2/2
v=sqrt(2gh)
KE= mv^2/2
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