Question
A rock is dropped off a 20m tall cliff. How long does it take to get to the bottom of the cliff? What is the instantaneous velocity right before it hits the bottom of the cliff?
Answers
Henry
a. h = 0.5g*t^2
h = 20 m
g = +9,8 m/s^2
Solve for t.
b. V^2 = Vo^2 + 2g*h
Vo = 0
g = +9.8 m/s^2
h = 20 m.
Solve for V.
h = 20 m
g = +9,8 m/s^2
Solve for t.
b. V^2 = Vo^2 + 2g*h
Vo = 0
g = +9.8 m/s^2
h = 20 m.
Solve for V.
Rob
yes
Anonymous
2 seconds?