Asked by Alex

A rock is dropped off a 20m tall cliff. How long does it take to get to the bottom of the cliff? What is the instantaneous velocity right before it hits the bottom of the cliff?
Answered by Henry
a. h = 0.5g*t^2
h = 20 m
g = +9,8 m/s^2
Solve for t.

b. V^2 = Vo^2 + 2g*h
Vo = 0
g = +9.8 m/s^2
h = 20 m.
Solve for V.
Answered by Rob
yes
Answered by Anonymous
2 seconds?
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