Asked by Mikhail
A pendulum that on Earth has period 0.52 s is taken to the surface of a large asteroid, where it is measured to have period 1.7 s. What is the value of the gravitational acceleration on the surface of that asteroid?
Answers
Answered by
Elena
T₁=2π•sqrt{L/g₁}
T₂=2π•sqrt{L/g₂}
g₂=g₁(T₁/T₂)²
T₂=2π•sqrt{L/g₂}
g₂=g₁(T₁/T₂)²