Asked by Ming

A pendulum on earth swings with angular frequency ω. On an unknown planet, it swings with angular frequency ω /2. The acceleration due to gravity on this planet is

A) 4g
B) 2g
C) g/2
D) g/4

I think it is C but I am not sure...
Answered by Henry
g/2^2 = g/4.
Answered by Omar
A pendulum on earth swings with angular frequency ω. On an unknown planet, it swings with angular frequency ω/2. The acceleration due to gravity on this planet is
4g (b)2g (c)g/2 (d) g/4

（please write down the process）