T₁=2πsqrt(m₁/k)
T₂ =2πsqrt(m₂/k)
T₂ /T₁ =sqrt{ m₂/m₁}
T₂ = T₁sqrt{ m₂/m₁}=
=3.5•sqrt(2/1) =4.95 s.
A certain pendulum with a 1.00 kg bob has a period of 3.50 s. What will happen to the period of the pendulum if the 1.00 kg bob is replaced by a bob with a mass of 2.00 kg? Explain your answer.
2 answers
T₁=2πsqrt(m₁/k)
T₂ =2πsqrt(m₂/k)
T₂ /T₁ =sqrt{ m₂/m₁}
T₂ = T₁sqrt{ m₂/m₁}=
=3.5•sqrt(2/1) =4.95 s.
T₂ =2πsqrt(m₂/k)
T₂ /T₁ =sqrt{ m₂/m₁}
T₂ = T₁sqrt{ m₂/m₁}=
=3.5•sqrt(2/1) =4.95 s.
1 answer