Asked by Zac
A certain pendulum on Earth has a period of 1.6 s. What would be the period of this pendulum if it were taken to another planet that had 1.75 times the mass of the Earth and 2.5 times the Earth's radius? Express your answer in seconds to three significant digits.
Answers
Answered by
Damon
frequency proportional to sqrt(g/L)
g proportional to mass of planet and 1/r^2
g planet = g earth * 1.75/6.25
= .28
sqrt gplanet = sqrt gearth
=.529
so frequency is .529 that on earth
period = 1/f
so
1.6/.529 = 3.02 seconds
g proportional to mass of planet and 1/r^2
g planet = g earth * 1.75/6.25
= .28
sqrt gplanet = sqrt gearth
=.529
so frequency is .529 that on earth
period = 1/f
so
1.6/.529 = 3.02 seconds
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