Question
An equation of the tangent line to the curve y=f(x)=x(4cosx−6sinx) at the point (3f(3)) is
y =?
Note: Please follow these instructions carefully:
(a) Express f(3) and f(3) in terms of . Simplify those expressions by evaluating the exact values of sin(3) and cos(3).
(b) Your answer should be in the form ax+m. When calculating a and m, approximate by 3.14.
y =?
Note: Please follow these instructions carefully:
(a) Express f(3) and f(3) in terms of . Simplify those expressions by evaluating the exact values of sin(3) and cos(3).
(b) Your answer should be in the form ax+m. When calculating a and m, approximate by 3.14.
Answers
Steve
y = x(4cosx-6sinx)
y(3) = 3(4cos3-6sin3) = -14.42
y' = -2(3x-2)cosx - 2(2x+3)sinx
y'(3) = 11.32
Now you have a point and a slope.
The equation of the line is cinchy.
y(3) = 3(4cos3-6sin3) = -14.42
y' = -2(3x-2)cosx - 2(2x+3)sinx
y'(3) = 11.32
Now you have a point and a slope.
The equation of the line is cinchy.
Sam
THANK YOU SO MUCH!