Asked by Mare
find tangent line equation to the curve at the given point:
y= 7e^x cos(x) P=(0,7)
y= 7e^x cos(x) P=(0,7)
Answers
Answered by
Damon
dy/dx = -7 e^x sin x + 7 e^x cos x
= 7 e^x (cos x - sin x)
at (0,7)
dy/dx = m the slope = 7 e^0 (cos 0 - sin 0)
= 7
so y = 7x+b
at(0,7)
7 = 7(0) + b
so b = 7
and
y = 7 x + 7
or
y = 7(x+1)
= 7 e^x (cos x - sin x)
at (0,7)
dy/dx = m the slope = 7 e^0 (cos 0 - sin 0)
= 7
so y = 7x+b
at(0,7)
7 = 7(0) + b
so b = 7
and
y = 7 x + 7
or
y = 7(x+1)
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