Question

An equation of the line tangent to the graph of f(x) = (4x2 - 8x + 3)4 at the point where x = 1 is:

Answer 1

dy/dx = 4(8 x -8) = 32 x -32
when x = 1, slope = 0 (horizontal line)
y = 4(4-8+3) = 4(-1) = -4
so the equation is y = -4

Answer 2

y=1

Answer 3

thx anon is right welp that's what apex said