Asked by Anonymous
equation of the tangent line to the curve y = 2x²-x+10 at the point (-1,13)
Answers
Answered by
Damon
dy/dx = slope = m = 4x-1
m = 4(-1) - 1 = -5
so
y = -5 x + b
find b
13 = -5(-1) + b
b = 8
so
y = -5 x + 8
m = 4(-1) - 1 = -5
so
y = -5 x + b
find b
13 = -5(-1) + b
b = 8
so
y = -5 x + 8
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