Asked by Tj

Consider an ideal spring that has an unstretched length l0 = 3.3 m. Assume the spring has a constant k = 23 N/m. Suppose the spring is attached to a mass m = 6 kg that lies on a horizontal frictionless surface. The spring-mass system is compressed a distance of x0 = 1.6 m from equilibrium and then released with an initial speed v0 = 4 m/s toward the equilibrium position.


(a) What is the period of oscillation for this system?



(b) What is the position of the block as a function of time. Express your answer in terms of t.


(c) How long will it take for the mass to first return to the equilibrium position?



(d) How long will it take for the spring to first become completely extended?
Answered by ss01
i got this question
did you got q4 & 5
Answered by Tj
only number 5 wich is (5/2)*R
Answered by ss01
the half loop one question and the spring block with friction one?
Answered by Tj
My bad.

I don´t know the other one

Half loop N= (k*d^2/m-2*g*R)*(m/R)
Answered by ss01
ocw.mit.edu/courses/physics/8-01t-physics-i-fall-2004/assignments/ps07sol.pdf

check q4 plug in your values, i got different values

i am figuring out the 2nd part
Answered by ss01
did you got vertical spring one?
Answered by rambo
did you get the 1st one.. plzz help anyone? plz
Answered by rambo
does anybody knows the last one(8th question) plzz. hop.
Answered by KUNOI
8th
a)(-C_1*r*v_x)/m
b)g-(C_1*r*v_y)/m
c)u*e^(-(C_1*r*t)/m)
d)((m*g)/(C_1*r))-((m*g)/(C_1*r))*e^(-(C_1*r*t)/m)
e)4.6*(m/(C_1*r))
f)0
g)(m*g)/(C_1*r)
Answered by ss01
did anyone got the vertical spring one?
Answered by mk
q:1
Answered by ss01
@mk did you got the spring block question?
Answered by rambo
kunoi ,, vertical one please.!! tried many times plzz help!
Answered by rambo
question 3rd not getting b,c and d

plzz help
Answered by rambo
We release an oil drop of radius r in air. The density of the oil is 720 kg/m3. C1 and C2 for 1 atmosphere air at 20∘ C are 3.40 × 10−4 (kg/m)/sec and 0.93 kg/m3, respectively.

How small should the oil drop be so that the drag force is dominated by the linear term in the speed (in lectures we called this Regime I). In this regime, the terminal velocity is mg/C1r. [m is the mass of the drop].

r<<x

find x ??

anyone?
Answered by Julia
r << 1.3e-4
Answered by rambo
julia, the grader is not accepting the answer
Answered by Anonymous
1.66*10^-4
Answered by rambo
yeah i got it,, forgot to take the cube root.

the 8th one plz
Answered by rambo
not getting the 3rd one and the 8th one.

got the first part of 3rd but not getting the rest.. plzzz help
Answered by yc
does anybody know the 8th one?
Answered by dude
can u give me brief equations on solving this oil drop?
Answered by yc
fine its here

r^3=3*(C1)^2/(4*pi*density*C_2*g)

solve by putting the values given and then,

TAKE THE CUBE ROOT OF THE VALUE YOU OBTAINED.

***the end***
Answered by anon
oscillating block ans D) 1.2
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