Asked by Anonymous
An ideal spring with a force constant (spring constant) of 15 N/m is initially compressed by 3.0 cm from its uncompressed position. How much work is required to compress the spring an additional 4.0 cm?
Answers
Answered by
Don
Potential Energy of the compressed string at x=3.0cm:
W = (1/2)*k*x^2
where k = spring constant = 15 N/m
x = distance = 3.0 cm
W = (1/2)*15*3^2
W = 67.5
Total work:
W_t = (1/2)*k*x^2
where x = 4+3 = 7
W_t= (1/2)*15*7^2
W_t = 367.5
W_t - W = 367.5 - 67.5
Work needed for the additional 4 cm is
300 J
W = (1/2)*k*x^2
where k = spring constant = 15 N/m
x = distance = 3.0 cm
W = (1/2)*15*3^2
W = 67.5
Total work:
W_t = (1/2)*k*x^2
where x = 4+3 = 7
W_t= (1/2)*15*7^2
W_t = 367.5
W_t - W = 367.5 - 67.5
Work needed for the additional 4 cm is
300 J
Answered by
Don
Whoops, I think my units are off because since
k is measured in N/m I need to convert cm to m
Answer should be .03 Joules
k is measured in N/m I need to convert cm to m
Answer should be .03 Joules
Answered by
Anonymous
Ty
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