see the other solution I gave.
Same exact problem, just a different point.
Find the standard form of the equation of the parabola with the given characteristics and vertex at the origin. Passes through the point (-1, 1/8); vertical axis.
There is no focus of the parabola or equation given, so how am I suppose to solve this problem?
2 answers
V(0,0), P(-1,1/8).
Y = a(x-h)^2 + k.
1/8 = a(-1-0)^2 + 0.
a = 1/8.
Y = 1/8(x-0)^2 + 0.
Y = (1/8)x^2.
Y = a(x-h)^2 + k.
1/8 = a(-1-0)^2 + 0.
a = 1/8.
Y = 1/8(x-0)^2 + 0.
Y = (1/8)x^2.
1 answer