Asked by ariana
find the standard form of the equation of the circle with a center at (6, -3) and a point on the circle at (-2,4)
(x-h)^2 + (y-k)^2=t^2
ok so using the distance between points i got
thank you
(x-6)^2+(y+3)^2=117
(x-h)^2 + (y-k)^2=t^2
ok so using the distance between points i got
thank you
(x-6)^2+(y+3)^2=117
Answers
Answered by
oobleck
(-2-6)^2 + (4+3)^2 = 113
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