Asked by Anonymous
Find the standard form of the equation of the parabola with given characteristics and vertex at the origin. Focus (5/2,0)
Answers
Answered by
oobleck
hello? why does my response not appear?
Answered by
oobleck
huh- Well, one more try
Since the vertex is at (0,0) you know the equation will be
x^2 = 4py
or
y^2 = 4px.
Since the focus is also on the x-axis, we have
y^2 = 4px
Since the focus is at (p,0) the equation is
y^2 = 4(5/2)x
or
y^2 = 10x
This can be verified at wolframalpha . com by typing in
parabola y^2 = 4px
Since the vertex is at (0,0) you know the equation will be
x^2 = 4py
or
y^2 = 4px.
Since the focus is also on the x-axis, we have
y^2 = 4px
Since the focus is at (p,0) the equation is
y^2 = 4(5/2)x
or
y^2 = 10x
This can be verified at wolframalpha . com by typing in
parabola y^2 = 4px
Answered by
oobleck
oops - I mean
parabola y^2 = 10x
parabola y^2 = 10x
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