Asked by Roy
Find dy/dx, if y= (sinx)^-1
Answers
Answered by
Jai
y = (sin x)^-1
This can also be rewritten as
y = 1/(sin x)
y = csc x
Therefore,
dy/dx = -cot(x) * csc(x)
Hope this helps~ :3
This can also be rewritten as
y = 1/(sin x)
y = csc x
Therefore,
dy/dx = -cot(x) * csc(x)
Hope this helps~ :3
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