Asked by Anonymous

If y=3/(sinx+cosx) , find dy/dx
A. 3sinx-3cosx
B. 3/(sinx+cosx)^2
C. -3/(sinx+cosx)^2
D. 3(cosx-sinx)/(sinx+cosx)^2
E. 3(sinx-cosx)/(1+2sinxcosx)
Answered by Steve
ever heard of the chain rule?

y = 3/u
y' = -3/u^2 u'

Now just plug in u = sinx+cosx