Asked by calculus
if y=cosx.sinx find dy/dx
Answers
Answered by
Steve
just use the product rule
If y = fg, then
y' = f'g + fg'
So,
dy.dx = -sinx.sinx + cosx.cosx
= cos^2x - sin^2x
= cos2x
Or, you could have noticed that
y = 1/2 sin2x, so
y' = cos2x
If y = fg, then
y' = f'g + fg'
So,
dy.dx = -sinx.sinx + cosx.cosx
= cos^2x - sin^2x
= cos2x
Or, you could have noticed that
y = 1/2 sin2x, so
y' = cos2x
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