Question
Find the derivative
y=sinx(sinx+cosx)
I got y'= cos(x)-sin^2(x)+2cos(x)sin(x)
is this righttttttt??
y=sinx(sinx+cosx)
I got y'= cos(x)-sin^2(x)+2cos(x)sin(x)
is this righttttttt??
Answers
Damon
sin (cos - sin) + cos (sin + cos)
-sin^2+cos^2 + 2 sin cos
I have cos^2
You have cos
-sin^2+cos^2 + 2 sin cos
I have cos^2
You have cos
Noe
So I just had the cos wrong?
Damon
as far as I know
Noe
Thanks