Find the derivative y=sinx(sinx+cosx) I

  1. tanx+secx=2cosx(sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx multiplying both sides by cosx sinx + 1 =2cos^2x sinx+1 =
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    2. shan asked by shan
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  2. Simplify #3:[cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sinx180sinx)tanx] =
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    2. Anonymous asked by Anonymous
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  3. Which of the following is the derivative of the function f(x)=sinx⋅(1−cosx) ? (1 point) Responses f′(x)=cosx⋅sinx f ' x
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  4. If y=3/(sinx+cosx) , find dy/dxA. 3sinx-3cosx B. 3/(sinx+cosx)^2 C. -3/(sinx+cosx)^2 D. 3(cosx-sinx)/(sinx+cosx)^2 E.
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    2. Anonymous asked by Anonymous
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  5. determine the absolute extreme values of the function f(x)=sinx-cosx+6 on the interval 0<=x<=2pi.This is what i did: 1.) i found
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    2. Sara asked by Sara
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  6. Q: If y=sinx/(1+tanx), find value of x not greater than pi, corresponding to maxima or minima value of y. I have proceeded thus-
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    2. MS asked by MS
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  7. I need to prove that the following is true. Thanks(cosx / 1-sinx ) = ( 1+sinx / cosx ) I recall this question causing all kinds
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    2. abdo asked by abdo
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  8. prove the identity(sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2 sinX^6= sinx^2 ^3 = (1-cosX^2)^3 = (1-2CosX^2 + cos^4) (1-cosX^2)
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    2. JungJung asked by JungJung
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  9. Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
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    2. Anonymous asked by Anonymous
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  10. I was given 21 questions for homework and I can't get the last few no matter how hard and how many times I try.17. Sinx-1/sinx+1
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    2. Kim asked by Kim
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