Asked by Anonymous
Find sin (x-y) if sinx = -2/5 and siny = 2/3 X is in quadrant IV, and y is in quadrant I
Answers
Answered by
Reiny
sinx = -2/5, x is in IV , so
cosx = √21/5
siny = 2/3 , y is in I , so
cosy = √5/3
sin(x-y) = sinxcosy - cosxsiny
= (-2/5)(√5/3) - √21/5)(2/3)
= ( -2√5 - 2√21)/15
cosx = √21/5
siny = 2/3 , y is in I , so
cosy = √5/3
sin(x-y) = sinxcosy - cosxsiny
= (-2/5)(√5/3) - √21/5)(2/3)
= ( -2√5 - 2√21)/15
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