Asked by Josh
1. A wire of length x is bent into the shape of a square. Express the area A as a function of x only.
2. A circle of radius x is inscribed in a square. Find the area inside the square but outside the circle as a function of x only.
2. A circle of radius x is inscribed in a square. Find the area inside the square but outside the circle as a function of x only.
Answers
Answered by
Reiny
1. the wire would have to be cut into 4 equal parts, making each side of the square x/4 units long
so Area = (x/4)^2 = x^2 /16
2. In this one, isn't the side of the square equal to 2x (the diameter of the circle) ?
You should be able to take it from here.
so Area = (x/4)^2 = x^2 /16
2. In this one, isn't the side of the square equal to 2x (the diameter of the circle) ?
You should be able to take it from here.
Answered by
Josh
So the area would be 4x^2 ?
and the area of a circle is pi * x^2
So would the area be (4-pi) x^2?
and the area of a circle is pi * x^2
So would the area be (4-pi) x^2?
Answered by
Reiny
yes
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