Question

a wire is bent into a rectangle.the ratio of the length of the rectangle to its breadth is 9:5.if the total length of the wire is 84cm,find the area of the rectangle formed by the wire
Two ways.
1)
L/B = 9:5 or L/B = 9/5 or 5L = 9B
Them L = 9B/5
Since the perimeter is 84, we have
L + L + B + B = 84
9B/5 + 9B/5 + B + B = 84
Solve for B = 15, then L = 27
Area = B X L = ?

2)
Call the sides length = 9x and breadth = 5x
L + L + B + B = 84
9x + 9x + 5x + 5x = 84
Solve for x = 3; then length = 3*9 = 27 and breadth = 3*5 = 15, then area = 27*15 = ?

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