Question
a wire is bent to form four semicircles all with diameters of 32 cm, how long is the wire? round to the nearest hundredth
Answers
Deepak
The length of the wire will be equal to the circumference of four semicircles that were made from it.
So, if the diameter of one semicircle is 32 cm, then the radius is = 32/2 cm = 16 cm.
Now, the circumference of a circle is 2*(pi)*(radius).
Here we have a semi-circle, so its circumference is half of of a circle = (pi)*(radius).
Then, circumference of 4 semi-circles is = 4*(pi)*(radius).
The value of pi is 22/7.
So, length of wire is = 4*(22/7)*16 cm = 200 cm (after rounding to the nearest hundreth).
So, if the diameter of one semicircle is 32 cm, then the radius is = 32/2 cm = 16 cm.
Now, the circumference of a circle is 2*(pi)*(radius).
Here we have a semi-circle, so its circumference is half of of a circle = (pi)*(radius).
Then, circumference of 4 semi-circles is = 4*(pi)*(radius).
The value of pi is 22/7.
So, length of wire is = 4*(22/7)*16 cm = 200 cm (after rounding to the nearest hundreth).
Anonymous
200.96
Anonymous
Well, what if the diameter is 53 cm?
Anonymous
Item 8
A wire is bent to form four semicircles. How long is the wire to the nearest hundredth?
length: about
cm
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