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An unknown amount of water is mixed with 310 mL of a 6 M solution of NaOH solution. A 75 mL sample of the resulting solution is...Asked by Gabriella
An unknown amount of water is mixed with
350 mL of a 6 M solution of NaOH solution. A 75 mL sample of the resulting solution is titrated to neutrality with 52.5 mL of 6 M HCl. Calculate the concentration of the diluted NaOH solution.
Answer in units of M
350 mL of a 6 M solution of NaOH solution. A 75 mL sample of the resulting solution is titrated to neutrality with 52.5 mL of 6 M HCl. Calculate the concentration of the diluted NaOH solution.
Answer in units of M
Answers
Answered by
DrBob222
HCl + NaOH ==> NaCl + H2O
mols HCl = M x L = ?
mols NaOH = mols HCl
M NaOH = mols NaOH/L NaOH
I believe that works out to be about 4.2M but check my work.
mols HCl = M x L = ?
mols NaOH = mols HCl
M NaOH = mols NaOH/L NaOH
I believe that works out to be about 4.2M but check my work.
Answered by
Quan
What are the steps to doing this... your answer is correct, I just want to know because I could really help me out with my chemistry test next week.
Answered by
ben dover
0.052L*6moles/1liter gives you 0.312 moles of HCL, meaning that is also the moles of NaOH. It gives you 0.075 L or 75 mL, 0.312/0.075 is 4.2M
I think.
I think.
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