Asked by Kelsie
An unknown volume of water at 18.2 degrees celsius is added to 24.4 mL of water at 35.0 degrees celsius. If the final temperature is 23.5 degrees celsius what was the unknown volume? (assume no heat is lost to surroundings and D of water is 1.00g/mL)
Answers
Answered by
DrBob222
Heat gained by water + heat lost by water = 0.
unknown mass H2O x specific heat x (Tf-Ti) + known mass water x specific heat x (Tf-Ti) = 0
Tf = final T
Ti = initial T.
You have only one unknown; i.e., unknown mass H2O. Post your work if you get stuck.
unknown mass H2O x specific heat x (Tf-Ti) + known mass water x specific heat x (Tf-Ti) = 0
Tf = final T
Ti = initial T.
You have only one unknown; i.e., unknown mass H2O. Post your work if you get stuck.
Answered by
Kelsie
x= unknown mass of H2O
x(4.184)(23.5-35) + 17.008(4.184)(23.5-18.2)=0
-48.116x + 377.156= 0
x = 7.84g
d=1.00g/mL x=unknown volume
1.00= 7.84/x
x=7.84mL
x(4.184)(23.5-35) + 17.008(4.184)(23.5-18.2)=0
-48.116x + 377.156= 0
x = 7.84g
d=1.00g/mL x=unknown volume
1.00= 7.84/x
x=7.84mL
Answered by
DrBob222
x= unknown mass of H2O
x(4.184)(23.5-35) + 17.008(4.184)(23.5-18.2)=0
<b>I don't think so. Tf = final T; Ti = initial T.
a. Isn't the initial T 18.2 and not 35 for the unknown amount of water?
b. Where did the 17.008 come from? That must be the mass of water but that was 24.4 mL so it has a mass of 24.4 mL x 1.00 g/mL = 24.4 grams.
c. And delta T for the known amount of water is 23.5 - 35.0 isn't it?</b>
-48.116x + 377.156= 0
x = 7.84g
d=1.00g/mL x=unknown volume
1.00= 7.84/x
x=7.84mL
x(4.184)(23.5-35) + 17.008(4.184)(23.5-18.2)=0
<b>I don't think so. Tf = final T; Ti = initial T.
a. Isn't the initial T 18.2 and not 35 for the unknown amount of water?
b. Where did the 17.008 come from? That must be the mass of water but that was 24.4 mL so it has a mass of 24.4 mL x 1.00 g/mL = 24.4 grams.
c. And delta T for the known amount of water is 23.5 - 35.0 isn't it?</b>
-48.116x + 377.156= 0
x = 7.84g
d=1.00g/mL x=unknown volume
1.00= 7.84/x
x=7.84mL
Answered by
Bobby
V = unknown volume of H2O, which equals the mass because the density is 1.00
V(4.184)(23.5-18.2) + 24.4(4.184)(23.5-35) = 0
22.1752V = 1174.0304
V = 52.94mL
V(4.184)(23.5-18.2) + 24.4(4.184)(23.5-35) = 0
22.1752V = 1174.0304
V = 52.94mL
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.